If ¯¯¯a,¯¯b,¯¯c are non-coplanar vectors such that ¯¯¯aׯ¯b=¯¯c,¯¯bׯ¯c=¯¯¯a,¯¯cׯ¯¯a=¯¯b, then |¯¯¯a|+2|¯¯b|−3|¯¯c| is equal to
A
1
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B
0
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C
2
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D
3
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Solution
The correct option is C0 The given condition is possible only when all three vectors ¯¯¯a,¯¯b,¯¯c are unit vectors, and that also they are mutually perpendicular to each other. Thus, |¯¯¯a|+2|¯¯b|−3|¯¯c|=1+2−3=0.