Question

If $p=2^a\times 3^b\times 5^c$ and $a>b>c$ are natural numbers, then what is the unit digit of p?

• A. 0
• B. 3
• C. 1
• D. 2

Answer 1

The correct option is A

0

Given: a, b and c are natural numbers and a > b > c

$\Rightarrow$ a, b and c are non - zero numbers.

$\Rightarrow$ p has 2, 3 and 5 as its prime factors.

Now, 2 $\times$ 5 = 10

Hence, 10 divides p.

$\therefore$ The number p should end with 0.