Question

If power developed across $6\Omega$ is 24 J/sec, then total power devloped in circuit is

• A. 48 W
• B. 72 W
• C. 144 W
• D. 216 W

Answer 1

The correct option is D 216 W


$P=i^{2}R=24$
$i^2\times 6=24$
$i^2=4$
i =2

$\Delta V$ Name across $6\Omega$
$2\times 6=i\times 3$
i =4

$P=P_1+P_2+P_3$
$=\left(2{)}^2\right(6)+4^2(3)+6^2(4)$
=24+48+144
=216 W