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Byju's Answer
Standard XI
Mathematics
Fundamental Laws of Logarithms
If product of...
Question
If product of roots of the equation
x
2
−
3
k
x
+
2
e
log
k
−
1
=
0
is
7
,
then
A
roots are integers and positive
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B
roots are integers and negative
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C
roots are rational not integers
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D
roots are irrational
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Solution
The correct option is
D
roots are irrational
x
2
−
3
k
x
+
2
e
log
k
−
1
=
0
a
=
1
,
b
=
−
3
k
and
c
=
2
e
log
k
−
1
Product of roots given
c
a
=
7
⇒
c
a
=
7
=
2
e
log
k
−
1
1
⇒
7
+
1
=
2
e
log
e
k
(
e
log
e
a
=
a
log
e
e
=
a
)
⇒
4
=
k
D
=
144
−
4
(
7
)
=
116
is not a perfect square.
⇒
Roots are irrational number
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Similar questions
Q.
If
k
>
0
and the product of roots of the equations
x
2
−
3
k
x
+
2
e
log
k
−
1
=
0
is
7
, then find the sum of the roots-
Q.
Assertion :If
a
and
b
are integers and the roots of
x
2
+
a
x
+
b
=
0
are rational then they must be integers. Reason: If the coefficient of
x
2
in a quadratic equation is unity then its roots must be integers.
Q.
If the product of the roots of the equation
x
2
−
3
k
x
+
2
e
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l
o
g
k
−
1
=
0
is
7
, then the roots of the equation are real if
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equals-
Q.
If the product of the roots for the equation x
2
– 3kx +2e
2ln(k)
-1=0 is 7, then the roots of the equation are real for k= ?
Q.
Statement-I : If roots of the equation
x
2
−
b
x
+
c
=
0
are two consecutive integers, then
b
2
−
4
c
=
1
.
Statement-II : If
a
,
b
,
c
are odd integers, then the roots of the equation
4
a
b
c
x
2
+
(
b
2
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4
a
c
)
x
−
b
=
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are real and distinct.
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