If R and h represent the horizontal range and maximum height respectively of an oblique projectile, then R28h+2h represents
A
Maximum horizontal range
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B
Maximum verticle range
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C
Time of flight
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D
Velocity of projectile at highest point.
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Solution
The correct option is A Maximum horizontal range We know that, R=v2sin2θg......(i) and h=v2sin2θ2g ⇒R28h=v2(2sinθcosθ)g×v2(2sinθcosθ)g×2g8v2sin2θ =v2cos2θg Now, R28h+2h=v2cos2θg+v2sin2θg=v2g Using eq. (i), we can say v2g is the maximum horizontal range of an oblique projectile.