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Question

If relative decrease in vapour pressure is 0.4 for a solution containing 1 mol NaCl in 3 mol H2O.

NaCl is_____ % ionized.

A
60%
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B
50%
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C
100%
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D
40%
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Solution

The correct option is B 60%
no. of moles of NaCl=1
relative lowering of vapour pressure =i×mole fraction of solute

relative lowering of vapour pressure= i×n(solute)n(solute)+n(solvent)
0.4=i×14
therefore i=1.6
degree of dissociation/ionisation=i1n1

NaClNa++Cl So, n=2

α=0.6
=60%
Option A is correct.

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