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Van't Hoff Factor

If relative d...

Question

If relative decrease in vapour pressure is 0.8 for a solution containing equimolar $N a C l a n d H_{2} O$ , then percentage ionization of $N a C l$ is:

A

0.3

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B

0.4

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C

0.5

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D

0.6

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Solution

The correct option is D 0.6
Abnormal colligative property
$Relative lowering of VP = i_{N a C l} \times χ_{N a C l}$
$0.8 = i_{N a C l} \times 0.5 i_{N a C l} = 1.6$
For dissociation :
$N a C l (a q .) \to N a^{+} (a q .) + C l^{-} (a q .) n = 2$

$i = 1 + α (n - 1)$
$1.6 = 1 + α (2 - 1) α = 0.6$

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Van't Hoff Factor

Standard XII Chemistry

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