If relative decrease in vapour pressure is 0.8 for a solution containing equimolar NaClandH2O, then percentage ionization of NaCl is:
A
0.3
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B
0.4
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C
0.5
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D
0.6
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Solution
The correct option is D 0.6 Abnormal colligative property Relative lowering of VP=iNaCl×χNaCl 0.8=iNaCl×0.5iNaCl=1.6
For dissociation : NaCl(aq.)→Na+(aq.)+Cl−(aq.)n=2