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Question

If s.d,of X is σ,then s.d.of the variable U=aX+bc where a,b,c are constants is

A
caσ
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B
acσ
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C
bcσ
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D
c2a2σ
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Solution

The correct option is C acσ
We know, Var(aX+b)=a2.Var(x)
Therefore we have Var{aX+bc}=a2c2var(X)=a2c2σ2
S.D{aX+bc}=acσ

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