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Question

If 2x23x+32=0 then x=?

A
3±i1522
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B
3±i1522
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C
3±i152
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D
3±i152
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Solution

The correct option is A 3±i1522
2x23x+32=0
x=3±94(32)(2)22 [From sreedhacharya method]
x=3±92422
x=3±1522
x=3±i1522

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