wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If tanx+tan2x+tan8x=tanx.tan2x.tan8x then the general solution of x=

A
nπ,nϵZ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
nπ,π4,nϵZ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
nπ11,nϵZ
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
nπ,π3,nϵZ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C nπ11,nϵZ
Given

tanx+tan2x+tan8x=tanxtan2xtan8x

Consider

tan(x+2x+8x)=tanx+tan2x+tan8xtanxtan2xtan8x1tanxtan2xtanxtan8xtan2xtan8x

tan(x+2x+8x)=tanxtan2xtan8xtanxtan2xtan8x1tanxtan2xtanxtan8xtan2xtan8x

tan(x+2x+8x)=0

tan11x=0

11x=nπ

x=nπ11

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
General Solutions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon