If the area of triangle $A B C$ is $96 s q . c m$ perimeter is $16 c m$ , then inradius is

10 c m

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11 c m

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12 c m

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13 c m

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Solution

The correct option is C $12 c m$
Area of a triangle $=$ $r$ x $s$
Where $r$ is the inradius and $s$ is the semi perimeter of the triangle
$96$ = $r$ x $(16 / 2)$
$r = 96 / 8 = 12 c m$
option (c) is correct.

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Similar questions

12 c m, 16 c m

10 c m

Two sides of a parallelogram are in the ratio 4 : 3. If its perimeter is 56 cm, find the lengths of its sides.

Δ A B C

A B + B C = 10 c m, B C + C A = 12 c m, C A + A B = 16 c m

Δ

ABCD

AB= 8 cm

AD= 10 cm

BD = 12 cm

DC = 13 cm

Δ DBC = 90^{\circ}

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