Question

If the distance between $(8,0)$ and A is $7$, the coordinates of the point A can not be?

• A. $(8,-7)$
• B. $(8,7)$
• C. $(1,0)$
• D. $(0,-8)$

Answer 1

The correct option is D $(0,-8)$

Let $A$ will be $(x,y)$

So, distance between $(x,y)$ & $(8,0)$ is $7$.

$i.e.,\sqrt{(8-x{)}^2+(0-y{)}^2}=7$

$(8-x{)}^2+y^2=7^2=49$

$\therefore (8-x{)}^2+y^2=49$

now, For $x=0$

$y^2\ne 49-64$

So, Option $\left(D\right)$ is wrong.