If the energy of a photon is given as 3.03 × 10–19 J then, the wavelength (λ) of the photon is :

6.56nm

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65.6nm

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656nm

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0.656nm

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Solution

The correct option is C 656nm

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Similar questions

3.03 \times 10^{- 19}

Δ E / a t o m = 3.03 \times 10^{- 19} ȷ {a t o m}^{- 1}

(λ)

h

6.6 \times 10^{- 34} J s

E = 3.03 \times 10^{- 19} J

(h = 6.6 \times 10^{- 34} s e c

C = 3 \times 10^{8} m / s e c .)

6000 o A

3.2 \times 10^{- 19}

4000 o A

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