If the initial number of template DNA molecules in a PCR reaction is 1000. What would be the number of product DNA molecules at the end of the 20 cycles closest to?
Each DNA multiplies in exponents of 2.
Number of C-DNA after n cycles of PCR ( if started from 1 double-stranded DNA )= 2n
Thus, for 20 cycles each DNA yields 220 copies.
Thus for 1000 DNA templates, we will have ,
1000 x 220= 1000 x 1048576 = 10.5 x 10^8 copies at the end of 20 cycles.
So, closest considering is option B i.e., '101010101010'.