Question

If the lengths of parallel sides of trapezium are $8cm,9cm$ and the distance between the parallel sides is $6cm$, then its area is

• A. $34{cm}^2$
• B. $68{cm}^2$
• C. $51{cm}^2$
• D. $72{cm}^2$

Answer 1

The correct option is C $51{cm}^2$

Area of trapezium $=\frac{1}{2}\times$ (sum of parallel sides)$\times$height

$=\frac{1}{2}(8+9)6$ sq.cm

$=\frac{1}{2}\times 17\times 6$ ${cm}^2$

$=51{cm}^2$