Question

If the ordinate (value of the '$y$' coordinate) is twice the abscissa (value of the '$x$' coordinate), then find the point where $7x-3y=8$.

• A. (8,16)
• B. (2,4)
• C. (3,6)
• D. (6,3)

Answer 1

The correct option is A

(8,16)

Let,
the abscissa $x=k$
the ordinate $y=2k$.

Putting the value in the given equation:
$\Rightarrow 7\left(k\right)-3\left(2k\right)=8$
$\Rightarrow k=8$

Therefore abcissa is $x=k=8$ and ordinate is $y=2k=16$.

Thus, the point is (8,16).