If the plane 2x-y-z-0 is a parallel to the line 2x-12-2-y2-z-1a- then the value of a is

lf the angle $θ$ between the line $\frac{x + 1}{1} = \frac{y - 1}{2} = \frac{z - 2}{2}$ and the plane $2 x - y + \sqrt{λ} z + 4 =$ $0$ is such that $sin θ = \frac{1}{3}$ , then value of $λ$ is

Q. If the plane

3 x - 4 y + 5 z = 0

is parallel to

\frac{2 x - 1}{2} = \frac{1 - y}{3} = \frac{z - 2}{a},

then the value of

a

is:

Q. The line

\frac{x - 4}{1} = \frac{y - 2}{1} = \frac{z - k}{2}

lies exactly in the plane

2 x - 4 y + z = 7

, then value of

k

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If the plane 2x−y+z=0 is a parallel to the line 2x−12=2−y2=z+1a, then the value of a is

The correct option is B −4Equation of Line is -x−121=y−2−2=z+1aThis line is parallel to the plane -2x−y+z=0Hence, it is perpendicular to the normal vector of the plane.Therefore,1(2)−2(−1)+a(1)=02+2+a=0a=−4

If the plane $2 x - y + z = 0$ is a parallel to the line $\frac{2 x - 1}{2} = \frac{2 - y}{2} = \frac{z + 1}{a}$ , then the value of $a$ is