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Question

If the point (2K3,K+2) lies on the graph of equation 2x+3x+15=0, find the value of x.

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Solution

Given point (2K3,K+2)
2x+3y+15=0
2(2K3)+3(K+2)+15=0
4K6+3K+6+15=0
7K+15=0
K=15/7

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