If the seventh person from the front in a queue is the tenth person from behind, how many are there in the queue ?

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Solution

The correct option is B 16
According to given question, the person is currently in $7^{t h}$ position in queue from the front.
So, there are $6$ persons in front of the person.
And the person is in $10^{t h}$ position in queue from back.
Therefore, there are $9$ persons behind the person
So, total number of persons in queue are : $6$ (Front) $+$ (the person himself) $+ 9$ (Back) i.e $16$

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