Question

In a queue, $A$ is eighteenth from the front while $B$ is sixteenth from the back. If $C$ is twentieth from the front and is exactly in the middle of $A$ and $B$, then how many persons are there in the queue?

• A. $45$
• B. $46$
• C. $47$
• D. $48$

Answer 1

Answer: (C)

$47$

$A$ is ${18}^{th}$ from front and $C$ is ${24}^{th}$.
Number of persons between $A$ and $C=6$.
Since $C$ is exactly in middle of $A$ and $B$, so number of persons between $C$ and $B=6$.
$\underleftrightarrow{17}$ $A$ $\underleftrightarrow{6}$ $C$ $\underleftrightarrow{6}$ $B$ $\underleftrightarrow{15}$
$\therefore$ Number of persons in the queue $=17+1+6+1+6+1+15=47$.