Question

If the sum of the numbers 2A and 33 gives 5B, then find A and B. Given that number 2A is divisible by 10.

• A. A = 0, B = 0
• B. A = 0, B = 4
• C. A = 4, B = 0
• D. A = 0, B = 3

Answer 1

The correct option is D A = 0, B = 3

Since 2A is divisible by 10, number 2A should have 0 in its ones place. So, A = 0.
Now 2A becomes 20 and 20 + 33 = 53
Hence, 5B = 53 and B = 3