If the sum of the numbers 2A and 33 gives 5B, then find A and B. Given that number 2A is divisible by 10.
A
A = 0, B = 0
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B
A = 0, B = 4
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C
A = 4, B = 0
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D
A = 0, B = 3
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Solution
The correct option is D A = 0, B = 3 Since 2A is divisible by 10, number 2A should have 0 in its ones place. So, A = 0. Now 2A becomes 20 and 20 + 33 = 53 Hence, 5B = 53 and B = 3