If the sum of the total number of protons and neutrons in in a pure sample of MgCl2 is 1.132×1026 then calculate the total number of moles of chlorine atoms present in the sample. (consider all Cl atoms to be Cl−35)
A
4 mol
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B
2 mol
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C
3 mol
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D
5 mol
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Solution
The correct option is A 4 mol The sum of protons and neutrons in Mg =12+12=24
The sum of protons and neutrons in Cl =17+18=35
The total sum of protons and neutrons in one molecule of MgCl2=24+35×2=94
The total sum of protons and neutrons in one mole of MgCl2=94×6.022×1023
92×6.022×1023 protons and neutrons are present in 1 mole of MgCl2.
So, 1.132×1026 protons and neutrons will be present in =1.132×102694×6.022×1023 mole of MgCl2 = 2 moles of MgCl2
Again 1 mole of MgCl2 contains 2 moles of Cl atoms.
So, 2 moles of MgCl2 will contain 4 moles of Cl atoms.