If the threshold frequency of a metal for photoelectric effect is v0, then which of the following will not happen?
If the frequency of incident radiation is further increased, the number of photoelectrons ejected will increase.
We will take all the options one by one for option (a), We know
KE = hν − hν0
If hν = hν0 [or v = v0]
KE = 0
Option (a) is correct.
For option (b), we know from Einstein's equation,
KE=hν−workfunction
KE=hν − hν0
It is also correct.
⇒ We know that, The number of electrons ejected is proportional to the intensity or brightness of light.
So option (c) is also correct.
⇒ The number of photoelectrons ejected only depends on intensity not on frequency. If the frequency is increased, Kinetic energy of photoelectrons ejected will increase.
Therefore option (d) is not correct.