If the two members of a Dobereiner's triad are chlorine and iodine, then the third member of this triad is :

fluorine

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bromine

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sodium

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calcium

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Solution

The correct option is B bromine
According to Dobereiner, the atomic mass of the middle element is nearly equal to the arithmetic mean of the other two. Therefore, the atomic mass of the third element is $=$ $\frac{35.5 + 127}{2}$ $=$ 81.25, which is the atomic mass of bromine.

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If the two members of a Dobereiner's triad are chlorine and iodine, then the third member of this triad is :

The correct option is B bromineAccording to Dobereiner, the atomic mass of the middle element is nearly equal to the arithmetic mean of the other two. Therefore, the atomic mass of the third element is = 35.5+1272 = 81.25, which is the atomic mass of bromine.

The correct option is B bromine
According to Dobereiner, the atomic mass of the middle element is nearly equal to the arithmetic mean of the other two. Therefore, the atomic mass of the third element is $=$ $\frac{35.5 + 127}{2}$ $=$ 81.25, which is the atomic mass of bromine.