If the values of $x, y & z$ are $2, 3 & 4$ respectively, then the value of $P = 3 x^{3} - 2 y^{2} + 5 z$ is

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Solution

The correct option is A 26
$P = 3 x^{3} - 2 y^{2} + 5 z$
$= 3 \times x^{3} - 2 \times y^{2} + 5 \times z$
At $x = 2, y = 3 & z = 4$
$P = 3 \times 2^{3} - 2 \times 3^{2} + 5 \times 4$
$P = 24 - 18 + 20 = 26$

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