If there are 666 bases in a mrna that codes for a protein with 222 amino acids and the base at position 601 is deleted such that the length of the rna becomes 665, how many codons will be altered?

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Solution

ishani if base at 601 position deleted from the place of deletion change in codans takesplace.so from the place of delition total 66 bases present .we know each codan with 3 bases.so total 22 codans change.if u are unable to understand remind me in class i will explain

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