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Question

If there are $$999$$ bases in an RNA that codes for a protein with $$333$$ amino acids, and the base at position $$901$$ is deleted such that the length of the RNA becomes $$998$$ bases, how many codons will be altered?


A
333
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B
1
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C
11
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D
33
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Solution

The correct option is D $$33$$
999 bases in RNA codes for a protein with 333 amino acids. If base at 901 position is deleted then first 900 bases will be normal while bases after 901th base will be altered that is 99 bases will be altered. 
3 bases stand for 1 codon, so, 99 bases = 33 codons will be altered due to deletion of one base at 901 position. 
Thus, option D is the correct answer. 

Biology

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