If there are 999 bases in an RNA that codes for a protein with 333 amino acids, and the base at position 901 is deleted such that the length of the RNA becomes 998 bases, how many codons will be altered?
A
333
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B
1
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C
11
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D
33
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Solution
The correct option is D33 999 bases in RNA codes for a protein with 333 amino acids. If base at 901 position is deleted then first 900 bases will be normal while bases after 901th base will be altered that is 99 bases will be altered.
3 bases stand for 1 codon, so, 99 bases = 33 codons will be altered due to deletion of one base at 901 position.