If two wires 1mm and 2mm thick are made of same mass of copper connected in series and current is passed through them, then heat produced in the wires is in the ratio.
A
2:1
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B
4:1
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C
8:1
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D
16:1
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Solution
The correct option is C16:1 Heat produced, H=i2RT=i2(ρlπ)t =i2ρVtA2(∵Al=V) H∝1r4 So, H1H2=(r2r1)4=(21)4=161.