If A-4 -3 - and B-6 -8 - then magnitude and direction of A-B- will beA- 25- tan -13-4B- 10- tan -15- 5 -5- tan -11-2D- 5- tan -13-4

The magnitudes of vectors $\to A, \to B a n d \to C$ are 3, 4 and 5 units respectively. If $\to A + \to B = \to C$ , the angle between $\to A$ and $\to B$ is

Q. Vectors

\to a

and

\to b

include an angle

θ

between them. If

(\to a + \to b)

and

(\to a - \to b)

respectively subtend angles

α

and

β

with

\to a

, then

(t a n α + t a n β)

is :

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If →A=4^i−3^j and →B=6^i+8^j then magnitude and direction of →A+→B will be

The correct option is B 5√5,tan−1(12) →A+→B=4^i−3^j+6^i+8^j=10^i+5^j|→A+→B|=√(10)2+(5)2=5√5 tanθ=510=12⇒θ=tan−1(12)

If $\to A = 4^i - 3^j$ and $\to B = 6^i + 8^j$ then magnitude and direction of $\to A + \to B$ will be

The correct option is B
$5 \sqrt{5}, t a n^{- 1} (\frac{1}{2})$

$\to A + \to B = 4^i - 3^j + 6^i + 8^j = 10^i + 5^j | \to A + \to B | = \sqrt{(10)^{2} + (5)^{2}} = 5 \sqrt{5}$
$t a n θ = \frac{5}{10} = \frac{1}{2} \Rightarrow θ = t a n^{- 1} (\frac{1}{2})$