If a-k-b-k-c-2-3-k- then a-b-c-

The correct option is D 6#160;i 2#160;j+6#160;k (a⃗×b⃗)×c⃗ #160; = [c⃗×(a⃗×b⃗)] = [a⃗(c⃗.b⃗) b⃗(c⃗.a⃗)] =b⃗(c⃗.a⃗) a⃗(c⃗.b⃗) =( ...

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Addition and Subtraction in Unit Vector Notation

If a⃗=î+ĵ+k...

Question

If $\to a =^i +^j +^k, \to b =^i -^j +^k, \to c =^2 i +^3 j -^k$ , then $(\to a \times \to b) \times \to c =$

2^i - 6^j + 2^k

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6^i - 2^j + 6^k

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- 6^i + 2^j - 6^k

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6^i + 2^j + 6^k

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Solution

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Similar questions

\to a = 2^i +^j + 3^k

\to b = 3^i + 2^j +^k

\to c =^i -^j - 4^k

\to d =^i + 2^j -^k

(\to a \times \to b) \times (\to c \times \to d) =

\to a = 3^i - 2^j +^k,

\to b = 2^i - 4^j - 3^k, \to c = -^i + 2^j + 2^k

\to a + \to b + \to c = 4^i - 4^j

\to a =^i -^j + 2^k, \to b = 2^i + 3^j +^k, \to c =^i -^k

\to a + 2 \to b - 3 \to c

\sqrt{78}

\to a =^i +^j -^k, \to b = -^i + 2^j + 2^k

\to c = -^i + 2^j -^k

\to a + \to b

\to b + \to c

\to a = 3^i + 2^j + 2^k, \to b = -^i + 3^j -^k, \to c =^i +^j +^k

\to a \times (\to b \times \to c)

(\to a \times \to b) \times \to c

\to a = 2^i +^j +^k

\to b =^i + 2^j + 2^k

\to c =^i +^j + 2^k

\to a \times (\to b \times \to c) = (1 + α)^i + β (1 + α)^j + r (1 + α) (1 + β)^k

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