If u-a-b- and v-a-b- and -a-b-2- then -u-v- -

|u⃗×v⃗| =|(a⃗ b⃗)×(a⃗+b⃗)| =|2a⃗×b⃗| =2 |a⃗| |b⃗| sin θ =8 sin θ = 8 √(1 cos^2 θ) = 8 √(1 (a⃗.b⃗4 )^2) (∵a⃗.b⃗=4 cos θ) = 2 √(16 (a⃗.b⃗)^2) ...

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Cross Product of Two Vectors

If u⃗=a⃗-b⃗ a...

Question

$I f \to u = \to a - \to b a n d \to v = \to a + \to b a n d | \to a | = | \to b | = 2, t h e n | \to u \times \to v | =$

$2 \sqrt{16 - (\to a . \to b)^{2}}$

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$\sqrt{16 - (\to a . \to b)^{2}}$

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$2 \sqrt{4 - (\to a . \to b)^{2}}$

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$\sqrt{4 - (\to a . \to b)^{2}}$

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$I f \to u = \to a - \to b a n d \to v = \to a + \to b a n d | \to a | = | \to b | = 2, t h e n | \to u \times \to v | =$

\to u = \to a - \to b, \to v = \to a + \to b

| \to a | = | \to b | = 2

| \to u \times \to v |

\to u = \to a - \to b; \to v = \to a + \to b

| \to a | = ∣ ∣ \to b ∣ ∣ = 2

| \to u \times \to v |

\to a

\to b

\to u = \to a - (\to a . \to b) \to b

\to v = \to a \times \to b,

| \to v |

\to u = \to a \times (\to b \times \to c) + \to b \times (\to c \times \to a) + \to c \times (\to a \times \to b)

\to u =

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