If u-a-b- v-a-b- and -a-b-2- then -u-v- is-

The correct option is A 2√(16 (a⃗·b⃗)^2) |u⃗×v⃗| = |(a⃗ b⃗)×(a⃗+b⃗)| |a⃗×b⃗ b⃗×a⃗| 2|a⃗×b⃗| = 2|a||b|sinθ sinθ = √(1 cos^2θ) ...

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Cross Product of Two Vectors

If u⃗=a⃗-b⃗...

Question

If $\to u = \to a - \to b, \to v = \to a + \to b$ , and $| \to a | = | \to b | = 2$ , then $| \to u \times \to v |$ is?

2 \sqrt{16 - (\to a \cdot \to b)^{2}}

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2 \sqrt{4 - (\to a \cdot \to b)^{2}}

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\sqrt{16 - (\to a \cdot {\to b}^{2}}

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\sqrt{4 - (\to a \cdot \to b)^{2}}

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{∣ ∣ \to a \times \to b ∣ ∣}^{2} = a^{2} b^{2} - {(\to a \cdot \to b)}^{2}

$I f \to u = \to a - \to b a n d \to v = \to a + \to b a n d | \to a | = | \to b | = 2, t h e n | \to u \times \to v | =$

\to u = \to a - \to b; \to v = \to a + \to b

| \to a | = ∣ ∣ \to b ∣ ∣ = 2

| \to u \times \to v |

\to a

\to b

\to u = \to a - (\to a . \to b) \to b

\to v = \to a \times \to b,

| \to v |

\to u = \to a \times (\to b \times \to c) + \to b \times (\to c \times \to a) + \to c \times (\to a \times \to b)

\to u =

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