If we start with 100 kg of ore (containing 7.5% rutile), pure TiO2 obtained is :
(Write your answer in kg and as nearest integer.)
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Solution
According to the balanced reactions, two moles of TiO2 (ore) forms two moles of high purity TiO2. So, if we start with 100 kg of ore (containing 7.5% rutile) produces =7.5×0.7×0.93=4.8825 kg TiO2.