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Byju's Answer
Standard VI
Mathematics
Order of Operations
If x=16, y=...
Question
If
x
=
16
,
y
=
10
,
z
=
5
and
t
=
−
1
, find the value of
(
x
−
y
)
(
5
√
x
−
y
)
+
√
(
x
−
y
u
)
(
z
+
t
)
.
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Solution
(
x
−
y
)
(
5
√
2
−
y
)
+
√
(
x
−
y
4
)
(
z
+
t
)
Here
x
=
16
;
y
=
10
;
z
=
5
;
t
=
−
1
=
(
16
−
10
)
(
5
√
16
−
10
)
+
(
√
(
16
−
104
)
(
5
−
1
)
=
(
6
)
(
5
×
4
−
10
)
+
√
16
−
104
(
4
)
=
√
60
+
2
√
16
−
104
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