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Question

If |x+2|+y=5 and x|y|=1, then find the value of x+y.

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Solution

|y|=x1

since |y| is always positive

x1 will always be a positive number

That means x is always greater than equal to 1

so now the equations become

x+2+y=5...(1)

xy=1...(2)

solving (1) and (2) we get,

x=2 and y=1

x+y=2+1=3

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