If X = -3 and Y = -4 are two perpendicular lines. Point P (-3, 1) lies on the line X = -3. Find the perpendicular distance(in units) from the point P to the line Y = -4.

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Solution

Line X = -3 is perpendicular to Y = -4. Therefore the point of intersection of the two lines is, say N, (-3, -4). Therefore the perpendicular distance from the point P to the line is Y = -4 can be said to be the distance between points P and N.

Distance between PN
= $\sqrt{(- 3 - (- 3))^{2} + (- 4 - 1)^{2}}$
= $\sqrt{(0)^{2} + (- 5)^{2}}$
= 5 units

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If X = -3 and Y = -4 are two perpendicular lines. Point P (-3, 1) lies on the line X = -3. Find the perpendicular distance(in units) from the point P to the line Y = -4. __

If X = -3 and Y = -4 are two perpendicular lines. Point P (-3, 1) lies on the line X = -3. Find the perpendicular distance(in units) from the point P to the line Y = -4.

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