If x3 - y3 - 1 - 3xy- where x- y determine the value of x - y - 1-

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Identity (x+a)(x+b)(x+c)

If x3 + y3 ...

Question

If $x^{3} + y^{3} + 1 = 3 x y,$ where $x \neq y$ determine the value of $x + y + 1.$

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Similar questions

x + y - 1 = 0

x^{3} + y^{3} + 3 x y = 1

x + y = 1

x^{3} + y^{3} + 3 x y = . . . . . . . . . . . .

If $\frac{x}{y} + \frac{y}{x} = - 1$ , where $x, y \neq 0$ then the value of $(x^{3} - y^{3})$ is
(a) $1$

(b) $- 1$

(d) $\frac{1}{2}$

\frac{x}{y} + \frac{y}{x} = - 1

x, y \neq 0

x^{3} - y^{3}

\frac{1}{2}

\frac{x}{y} + \frac{y}{x} = - 1, (x, y \neq 0)

x^{3} - y^{3}

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