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Question

If x+y=4 and xy=2, find the value of x2+y2.

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Solution

x+y=4Squaring on both sides,(x+y)2=(4)2 x2+y2+2xy=16 x2+y2+2×2=16 ( xy=2) x2+y2+4=16 x2+y2=164=12 x2+y2=12


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