If y - sec-1 x2- x - 0- find dydx

Given that, y=(sec^ 1x)^2 So, y'=dydx=2sec^ 1x1|x|√(x^2 1) ...

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Higher Order Derivatives

If y = sec-...

Question

If $y = (s e c^{- 1} x)^{2}, x > 0$ , find $\frac{d y}{d x}$

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y = {sin}^{- 1} (x^{2} \sqrt{1 - x} - \sqrt{x} \sqrt{1 - x^{4}}),

\frac{d y}{d x} .

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