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Byju's Answer
Standard XII
Mathematics
Parametric Differentiation
If y=x e x, t...
Question
If
y
=
x
e
x
, then
d
y
d
x
=
A
y
(
l
o
g
x
+
e
x
)
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B
y
l
o
g
x
(
1
2
+
e
x
)
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C
y
e
x
(
l
o
g
x
+
x
)
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D
y
e
x
(
l
o
g
x
+
1
x
)
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Solution
The correct option is
D
y
e
x
(
l
o
g
x
+
1
x
)
l
o
g
y
=
e
x
l
o
g
x
∴
1
y
d
y
d
x
=
e
x
l
o
g
x
+
e
x
.
1
x
=
e
x
(
l
o
g
x
+
1
x
)
∴
d
y
d
x
=
y
e
x
(
l
o
g
x
+
1
x
)
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1
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