39
Question
If z1=2−i,z2=−2+i,find
Im(1z1¯z2)
Im(1z1¯z2)
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Solution
z1=2−i,z2=−2+i
Im(1z1¯z2),¯z2=−2−i
Now z1.¯z2=(2−i)(−2−i)=2(−2−i)−i(−2−i)=−4−2i+2i+(i)2=−4−1=−5∴(1z1¯z2)=1−5+0iIm(1z1¯z2)=0
z1=2−i,z2=−2+i
Im(1z1¯z2),¯z2=−2−i
Now z1.¯z2=(2−i)(−2−i)=2(−2−i)−i(−2−i)=−4−2i+2i+(i)2=−4−1=−5∴(1z1¯z2)=1−5+0iIm(1z1¯z2)=0
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