Question

If Z satisfied the equation $\left(\frac{Z-2}{Z+2}\right)\left(\frac{\overline{Z}-2}{\overline{Z}+2}\right)$then minimum, value of$|Z|$is equal to

• A. 0
• B. 2
• C. 4
• D. 6

Answer 1

Answer: (A)

0

$(Z-2)[\overline{Z}-\overline{2}](Z-+2)[\overline{Z}-2]$
$|Z-2{|}^2=|Z+2|\Rightarrow |Z-2|=|Z+2|$
Line on imaginary axis
$|Z_1|min=0$