Question

In a $3$-digit number, the ten's digit is twice the unit digit and the hundred's digit is thrice the unit's digit. If the sum of its all three digits is $12$, then find the reversed number.

• A. $642$
• B. $462$
• C. $246$
• D. $416$

Answer 1

Answer: (C)

$246$

Let the unit's place digit be $x$, the tenth place digit be $y$ and the hundredth place digit be $z$ of the three digit number

So the number will be $100z+10y+x$

Now given, sum of digits $=x+y+z=12$......(1)

And $y=2x,z=3x$

Now using (1)

$\Rightarrow x+2x+3x=12$

$\Rightarrow 6x=12\Rightarrow x=2$

So $y=2x=4$ and $z=3x=6$

Hence the number is $=100z+10y+x=642$

So the reversed number is $246$