Question

In a $3$-digit number, the ten's digit is twice the unit digit and hundred's digit is thrice the unit's digit. If the sum of its all three digits is $6$, then find the reversed number.

• A. $123$
• B. $321$
• C. $132$
• D. $312$

Answer 1

The correct option is A $123$

Let the number be $abc$ i.e., $100a+10b+c$
Where unit digit $=c$, ten's digit $=b$ and hundred's digit $=a$.
Given, $b=2c$ and $a=3c$
$a+b+c=6$ .....(1)
Substitute the values of $b$ and a in equation (1), we get
$3c+2c+c=6$
$\Rightarrow 6c=6$ .....(Divide both the sides by $6$)
$\Rightarrow c=1$
Therefore, $b=2c=2\times 1=2$
and $a=3c=3\times 1=3$
Hence, the required $3$-digit number is $321$.
So, the reversed number is $123$.