Question

In a block of alminimum measures 4.0 cm ? 5.0 cm ? 2.0 cm is completely submerged in a tank of water, what volume of water does it displace ? What is the weight of the displaced water ? How large of a buoyant force acts on the block ?

Answer 1

Dear student,

$$\begin{gathered} volumeofthewaterdisplaced=Volumeoftheblock \\ volumeofthewaterdisplaced=4\times 5\times 2=40c{m}^3 \\ \left(ii\right)massogfthewaterdisplaced=Volume\times Densityofwater \\ massofthewaterdisplaced=40\times 1=40gm=4\times {10}^{-2}Kg \\ Weightofthewaterdisplaced=mg=4\times {10}^{-2}\times 10=0.4N \\ \left(iii\right)Buoynantforce=Weightofthewaterdisplaced=0.4N \end{gathered}$$

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