Question

In a Bohr's model of atom when an electron jumps from n=1 to n=3, how much energy will be emitted or absorbed

• A. $2.15\times {10}^{-11}erg$
• B. $0.1911\times {10}^{-10}$ erg
• C. $2.389\times {10}^{-12}$ erg
• D. $0.239\times {10}^{-10}$ erg

Answer 1

The correct option is B

$0.1911\times {10}^{-10}$ erg

According to Bohr's model $△E=E_1-E_3$

$=2.179\times {10}^{-11}-\frac{2.179\times {10}^{1}1}{9}$

$=\frac{8}{9}\times 2.179\times {10}^{-11}=1.91\times {10}^{-11}=0.191\times {10}^{-10}erg$

Since electron is going from n=1 to n=3 hence energy is absorbed.