Question

In a certain loaded transformer, the secondary voltage is one-fourth the primary voltage. The secondary current is

• A. one-fourth the primary current
• B. four times the primary current
• C. equal to the primary current
• D. one-fourth the primary current and equal to the primary current

Answer 1

The correct option is B four times the primary current

Turns ratio, $n=\frac{N_p}{N_s}=\frac{V_p}{V_s}=\frac{I_s}{I_p}$ where p for primary coil and s for secondary coil.

Here, $V_s=V_p/4$ or $V_p/V_s=4$

So, $4=I_s/I_p$ or $I_s=4I_p$